Question

how is the value of slope of kmax of photo electron-frequency of photon graph equal to plancks constant​

Answer 1

Explanation:

Correct option is

D

charge of electron

hv=hv

0

+ev

0

v

0

=

e

h

v−

e

h

v

0

On comparing this equation with the straight line equation, i.e y=mx+c

The slope of v

0

vs v is (v

0

is stopping potential)

(slope)

1

=

e

h

or K

max

=hv−hv

0

Thus, slope of K

max

vs v is