Question

How is the work done by a force measured
when
1.is in the direction of displacement
2.is it an angle to the direction of displacement​

Answer 1

Answer:

W=F*dcos(theta)

Explanation:

Its universal formula

Answer 2

Explanation:

Ok those who don't know the answer see the below it quite easy :-

It looks like the force done by a spring, there is a displacement at which the force will become zero, let’s call it D while the actual displacement is called d, then the force is

f=(D-d)*F/D were F is the force at beginning (d=0)

The force versus displacement looks like a triangle starting with f=F at origin and with f=0 at d=D

Work done is the area under the hypotenuse W=INT(f*Delta ) between d1 and d2 (the two displacements between you want to calculate the work) and that is a trapezium with height d2-d1 and basis calculated with initial formula (f=…) replacing d for actual values d1 and d2 obtaining f1 and f2.

The area of trapezium is calculated A=(B+b)*H/2

Were B=f1 b=f2 and H=d2-d1

Mark as brainliest.