Math, asked by mannavvmodi, 18 hours ago

How is this false?
 \sqrt{4 - 2 \sqrt{3} }  = 1 -  \sqrt{3}

Attachments:

Answers

Answered by z1116000
0

Answer:

I start with x=4+23–√−−−−−−−√−3–√, then

x+3–√(x+3–√)2x2+(23–√)x+3x2+(23–√)x−1−23–√=4+23–√−−−−−−−√=(4+23–√−−−−−−−√)2=4+23–√=0

So I have shown that there is some polynomial whose solution is x=4+23–√−−−−−−−√−3–√, but I have not shown it to be 1.

Step-by-step explanation:

mark me brainliest please

Similar questions