Question

How is time period of a simple pendulum affected if 'g' is reduced to one-fourth? ​

Answer 1

Answer:

Explanation:

We know time period T=2π$\sqrt{l/g}$

So T is inversely proportional to $\sqrt{g}$

So (T1/T2)^2=g2/g1

Given g2=g1/4

(T1/T2)^2=1/4

(T1/T2)=1/2

So T2=2T1

Implies time period becomes twice

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