Question

How is x^2+1 equal to 2x-1?​

Answer 1

Answer:

I’m assuming you meant the following equation based on your formatting:

(2x-1)/3 = (x-2)/1+1

First, perform the addition:

(2x-1)/3 = (x-2)/2

Next, multiply both sides by the LCD which is 6:

6(2x-1)/3 = 6(x-2)/2

2(2x-1) = 3(x-2)

Now distribute the terms:

4x-2 = 3x-6

Add 6 to both sides:

4x+4 = 3x

Subtract 4x from both sides:

-1x = 4

Divide by -1:

x = -4

Now prove this by substituting for x in the original equation:

(2x-1)/3 = (x-2)/1+1

x = -4

(2*-4–1)/3 = (-4–2)/1+1

Perform the addition in the denominator, and then the operations in the parentheses using PEMDAS:

(2*-4–1)/3 = (-4–2)/2

(-8–1)/3 = (-6)/2

(-9)/3 = (-6)/2

Remove the parentheses, and then divide:

-9/3 = -6/2

-3 = -3

So x = -4

Step-by-step explanation:

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Answer 2

Answer:

x=-4

Step-by-step explanation:

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