how is x+5 a factor of
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Answer:
Let us assume that x + 5 is a factor,
Then x = - 5 is a zero of the polynomial
p(x) = x³ + 2x² - 33x - 90
p(-5) = (-5)³ + 2(-5)² - 33(-5) - 90
= -125 + 50 + 165 - 90
= 215 - 215
= 0
Therefore x+5 is a factor of the given polynomial
Hope it helps....
Answered by
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x³ + 2x² - 33x - 90
=> x³ + 3x² - x² - 3x - 30x - 90
=> (x³+3x²) + (-x²-3x) + (-30x-90)
=> x²(x+3)-x(x+3)-30(x+3)
=> (x-3)(x²-x-30)
=> (x-3)(x²-6x+5x-30)
=> (x-3)[x(x-6)+5(x-6)]
=> (x-3)(x-6)(x+5)
I hope it will be helpful for you
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