Question

How ( K+ 1 ) ( K+ 2 ) =( K+1 )

Answer 1

since,(K+1)(K+2)-(K+1)=0
(K+1)(K+1)=0
Thus,
Ksquare+3K+2=K+1
Ksquare+2K+1=0
Ksquare+K+K+1=0
K(K+1)+(K+1)=0
(K+1)(K+1)=0
Hence proved