How kinetic energy increased 4 times when the speed of an object doubles?
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HEYA MATE
_____________________________ as speed is doubled so,
v'=2v
hence kinetic energy =1/2mv^2
which becomes,,,
1/2m(2v)^2
1/2m*4*v^2
4(1/2mv^2)
hence kinetic energy becomes 4 times....
____________________________
hope it helps u mate
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