Question

how log (15-5) = log20-log2

Answer 1

rhs
value of x log is 15-5= 5
so value of log x is 5.

lhs
value of log y=log 20-log 2 = 5
so maybe the value of log 20 can be 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7,6, 5
and value of log 2 can be 15, 14, 13, 12, 11, 10, 9 , 8, 7, 6, 5, 4, 3, 2, 1, 0 respectively

Answer 2

$\log (15-5) = \log 20-\log 2,$ verified.

Step-by-step explanation:

We have,

$\log (15-5) = \log 20-\log 2$

Verify,$\log (15-5) = \log 20-\log 2$

∴ $\log (15-5) = \log 20-\log 2$

⇒ $\log 10 = \log 20-\log 2$

⇒ $\log 10 = \log \dfrac{20}{2}$

[∵ $\log m-\log m= \log \dfrac{m}{n}$]

⇒ $\log 10 = \log 10$

⇒ 1 = 1, verified.

[∵$\log 10 =1$]

Hence, $\log (15-5) = \log 20-\log 2,$ verified.