How long did Shatabdi Express take for the 6000 kms journey with 10 stop overs? If the ih stopover lasted i2 minutes where 'i' is odd and 'i' minutes when 'i' is even and the average speed between any two stopovers was 90kmph.
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Given:- distance= 6000kms
i is even
To find:- time taken
Solution:- The total distance is 6000km and stops taken are 10 with average speed being 90kmph.
The i^th stop is i^2 i.e.
The 1st stopover lasts 1^2 = 1 minute
The 2nd stopover lasts 2^2 = 4 minutes
The 3rd stopover lasts 3^2 = 9 minutes
and so on,
The average speed between any two stopovers was 90km/hr.
Using the distance formula,
D = R*T
6000 = T*(90)
T = 6000/90
T = 66.67
In both cases information is not sufficient and hence more parameters are required. i.e the time taken byt the train for every stopage.
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