Question

how long does it take a cyclist to interease his velocity from 4.0 m / s to 10m / s if he accelerates at 3.0 m / s2 .

Answer 1

Answer:

Time taken to attain velocity of 10 m/s is 2 sec.

Explanation:

we know that,

$\bold{\boxed{v=u+at}}$

Given,

$u=4.0 m/s$

$v=10 m/s$

$a=3.0 m/{s}^{2}$

so,

$10=4+3(t)$

$10-4=3(t)$

$6=3(t)$

$t=2sec$

HOPE THAT HELPS!!

Answer 2

Answer :

›»› The time taken by the cyclist = 2 sec

Given :

• Initial velocity of cyclist = 4.0 m/s
• Final velocity of cyclist = 10 m/s
• Acceleration of cyclist = 3.0 m/s²

To Calculate :

• Time taken by cyclist = ?

How to Calculate?

❒ To Calculate the time taken by cyclist we will use first equation of motion which says v = u + at

Here,

• v is the Final velocity in m/s.
• u is the Initial velocity in m/s.
• a is the Acceleration in m/s².
• t is the Time taken in second.

Let's calculate Time taken...

Calculation :

$\tt{:\implies v = u + at}$

⠀

$\tt{:\implies 10 = 4.0 + 3.0 \times t}$

⠀

$\tt{:\implies 10 = 4.0 + 3.0t}$

⠀

$\tt{:\implies 10 - 4.0 = 3.0t}$

⠀

$\tt{:\implies 6 = 3.0t}$

⠀

$\tt{:\implies t = \cancel{\dfrac{6}{3.0} }}$

⠀

$\frak{:\implies \underline{ \boxed{ \pink{ \frak{t = 2 \: sec}}}}}$

║Hence, the Time taken by the cyclist us 2 sec.║

⠀

⠀

Additional Information :

★ Second equation of motion :

⪼ s = ut + ½ at²

Where,

• s is the Distance travelled in m.
• u is the Initial velocity in m/s.
• t is the Time taken in second.
• a is the Acceleration in m/s².

★ Third equation of motion :

⪼ v² = u² + 2as

Where,

• v is the Final velocity in m/s.
• u is the Initial velocity in m/s.
• a is the Acceleration in m/s².
• s is the Distance travelled in m.