Question

how long has a current of 3 ampere to be applied through a solution of silver nitrate to a coat a metal surface of 0.42g(atomic mass of Ag=108)​

Answer 1

Answer:

Mass of silver to be deposited

=volume×density

=area×thickness×density

Given: Area=80cm

2

,thickness=0.0005 cm and density=10.5 g/cm

3

Mass of silver to be deposited =80×0.0005×10.5

=0.42 g

Applying to silver E=Z×96500

Z=

96500

108

g

Let the current be passed for t seconds.

We know that, W=Z×I×t

So, 0.42=

9600

108

×3×t

or t=

108×3

0.42×96500

=125.09 second.

Answer 2

$t=0.42×965003×108 \\ =40530324 \\ =125.09 sec$