How long in hour must a current of 0.60 ampere be maintained to electroplate 66g of gold from a solution of gold chloride?
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Answered by
2
Here,
I=0.60 amp.; A=197; n=3; W=66g; F=96500C; t=?
So, W=A/nF×I×t
So, 66=197×0.6×t/3×96500
So, t=66×3×96500/197×0.6 sec=66×3×96500/197×0.6×3600 hr=44.9 hr.
Hope it helps.....
Cheers
I=0.60 amp.; A=197; n=3; W=66g; F=96500C; t=?
So, W=A/nF×I×t
So, 66=197×0.6×t/3×96500
So, t=66×3×96500/197×0.6 sec=66×3×96500/197×0.6×3600 hr=44.9 hr.
Hope it helps.....
Cheers
Answered by
0
Hey mate!
Here's your answer!!
Given,
I=0.60 amp.; A=197; n=3; W=66g; F=96500C
To find,
t=?
We know that,
W=A/nF×I×t
So, 66 = 197 × 0.6 × t/3 × 96500
So, t = 66 × 3 × 96500/197 × 0.6
t = 66 × 3 × 96500/197 × 0.6×3600 hr
= 44.9 hr
Hope it helps you!!!
Here's your answer!!
Given,
I=0.60 amp.; A=197; n=3; W=66g; F=96500C
To find,
t=?
We know that,
W=A/nF×I×t
So, 66 = 197 × 0.6 × t/3 × 96500
So, t = 66 × 3 × 96500/197 × 0.6
t = 66 × 3 × 96500/197 × 0.6×3600 hr
= 44.9 hr
Hope it helps you!!!
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