How long, in hours, would be required for the electroplating of 78 g of platinum from a solution of [PtCl6]2-, using an average current of 10 amperes at an 80% electrode efficiency?
(a) 8.4
(b) 5.4
(c) 16.8
(d) 11.2
(e) 12.4
Answers
Answered by
6
Answer:
8.4 is the correct answer of this question.
Please mark me as brainlist.
I really need it
Answered by
0
Answer:
b)55.4
Explanation:
The oxidation state of Pt in [PtCl6]2- is +4.
Pt^+4+4e¯ ->Pt
E=M/Z=195g/4=48.75
electrode efficiency =80%
E=80%×48.75g=39
m/E=It/
t=mF/EI
t=78g×96500C/39g×10
=19300sec
t=19300sec×1hr/3600sec=5.36hr
Similar questions