Question

How long will an e take to fall through a distance of 2m in a uniform field of 280N/c

Answer 1

Answer:

1.18X10⁻⁵

Explanation:

d=at²/2

t²= 2d/a

    =2dm/F

    =2dm/qE               (E=F/q)

 t =√2dm/qE

  on putting d=2m

                    m=1.6X10⁻²⁷

                    q=1.6X10⁻¹⁹

                    E=280

you get t=1.18X10⁻⁵