Question

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average
acceleration of 3.2 m/s2
?


pls ans fast​

Answer 1

Answer:

Time taken = 2.59 s

Explanation:

u = 15.2 m/s

v = 23.5 m/s

v = u + at

v - u / a = t

t = 8.3 / 3.2 = 2.59 s

Answer 2

The time required = 2.59 sec

Given :

A car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s²

To find :

Calculate the time is required to accelerate

Solution :

Step 1 of 2 :

Write down change in velocity and acceleration

Here it is given that a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s²

Initial velocity = 15.2 m/s

Final velocity = 23.5 m/s

Change in velocity

= Δv

= 23.5 m/s - 15.2 m/s

= 8.3 m/s

Acceleration = a = 3.2 m/s²

Step 2 of 2 :

Calculate the time is required to accelerate

Let time is required to accelerate = t sec

Then by the given condition

$\displaystyle \sf{ a = \frac{ \Delta v}{t} }$

$\displaystyle \sf{ \implies 3.2 = \frac{8.3}{t} }$

$\displaystyle \sf{ \implies t= \frac{8.3}{3.2} }$

$\displaystyle \sf{ \implies t= 2.59 }$

Hence the required time = 2.59 sec

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