Question

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s 2 ?

Answer 1

Given:-

• Initial velocity ,u = 15.2m/s

• Final velocity ,v = 23.5m/s

• Acceleration ,a = 3.2m/s

To Find:-

• Time taken by the car ,t.

Solution:-

By using 1st equation of motion

→ v = u+at

Substitute the value we get

→ 23.5 = 15.2 + 3.2 ×t

→ 23.5-15.2 = 3.2×t

→ 8.3 = 3.2×t

→ t = 8.3/3.2

→ t = 2.59 s

∴ Time taken by the car is 2.59 second.

Answer 2

☄ᎯᏁᏕᏯᎬᏒ ☄

Let u = Initial velocity, v = Final velocity, a = Acceleration & t = Time taken.

⋆ u = 15.2 m/s

⋆ v = 23.5 m/s

⋆ a = 3.2 m/s²

☄ t = ?

☃ $\pink{\boxed{ \color{gray} {\rm{t = \frac{v - u}{a}}}}}$

⇢$\rm t = \frac{23.5 - 15.2}{3.2}$

⇢$\rm t = \frac{8.3}{3.2}$

☀ $\rm \red{t = 2.59 \: seconds}$