Question

how long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5km/hr2?

Answer 1

As always, if the relation does not come to mind immediately, take a glance at the basic kinematic equations of constant acceleration:

So: what do we know? Vi start speed; Vf terminal speed; acceleration a; and we want to know time t. Three of the relations have a term in d distance - which we don’’t know. That leaves this one: Vt = Vi + a*t. Here we go then:

44 = 0 + 5 * t so t = 44 / 5 = 8.8 hours (not seconds - thanks to Harry Sharp).

Bigger thanks to Mazmanian and Ward for noting the ridiculosity inherent in this problem as written. Guilty as charged for plug and chugging this silly question.

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Answer 2

★ Answer :

• $\boxed{\textsf{\textbf{Time taken (t) = 8.8 hr}}}$

★ Given :

• Initial velocity (u) = 0 km/hr
• Final velocity (v) = 44 km/hr
• Acceleration (a) = 5 km/hr²

★ To Find :

• Time taken (t) = ?

★ Step by step explaination :

From equation of motion we have:

$\bigstar \: \boxed{\boxed{ \bold{v = u + at}}} \: \bigstar$

By substituting value of u, v & a in the equation we get:

→ 44 = 0 + 5t

→ 44 = 5t

→ 5t = 44

→ t = 44/5

→ t = 8.8 hours

⛬ Time taken by the car is 8.8 hours.