Question

How long will it take a force of 10n to stop a mass of 2.5kg which is moving at 20m/s?

Answer 1

Hello friend

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Here is your answer!!

First write all the given values.

Force(F) = 10 N

Mass(m) = 2.5 kg

Initial velocity (u) = 20m/s

(Initial velocity we have taken because the object is moving not completed the work)

Final velocity (v) = 0

We have to find,

time (t) = ?

We know that,

v = u + at

This formula can be used to find time but for this we need acceleration (a)

So,we know that

F = ma

a = f/m

a = 10/2.5

a = 4 m/s^2

So,we have calculated the acceleration and now we can easily find the time and for that we will use the equation of,

v = u + at

By putting the given values we get,

0 = 20 + 4 x t

4t = 20

t = 20/4

t = 5 sec

Therefore, the object will take 5 sec to stop a mass of 2.5 kg which is moving at 20m/s.

I hope this will help you..

Thanks..

:)

Answer 2

So here is your ans

F=10N

M=2.5KG

U=20m/s

V=0

T=?

So,

F=ma

A=F/m

A=100/25

A=4

So by using 1st equation of motion.

V=u+at

0=20+4(t)

4t=20

T=20/5

T=5

Therefore the object will take t sec to stop a mass of 2.5 kg which is moving at 20m/s

Hope it will help