Question

how long will it take for a wooden block of 2kg to slide from the rest distance of 3 metre down a rough inclined at 30 degree to the horizontal given coefficient of friction equal to 0.2​

Answer 1

Answer:

Explanation:

m=2kg d=3m,mue=0.2

forces on block is

mgsin@ -mui mgcos@=ma

10(3)^1/2/2 -(0.2)10/2=a

7.32/2=a

s=ut+at^2/2

as starting the motion from rest therefore u=0

(6/3.66)^1/2 =t

t=1.639