Question

HOW LONG WILL IT TAKE TO REACH THE GROUND OF A STONE OF MASS 5KG THROWN FROM THE TOP OF A BUILDING OF 64M HEIGH

Answer 1

Answer:

m = 5 kg

h = 50 m

velocity = v just before hitting the ground 

 v² = u² + 2 g h = 0 + 2 * 9.8 * 50 = 980

When the stone is penetrating the sand:

v² = u² + 2 a s

0 = 980 + 2 * a * 1

a = - 490 m/s²

Average resistance Force offered by sand = m a = - 5 * 490

  =- 2, 450 N

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Explanation:

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