Question

How long would it take a car, starting from rest and accelerating uniformly in a straight line at 5 m/s^-2 to cover a distance of 200 m?

Answer 1

Answer:

~ 9 seconds

Explanation:

using formula :

s = u(t) + 1/2(a) (t)^2

where u = 0

a = 5 m/s^2

s = 200

Answer 2

The time taken by the car is 8.94 seconds.

Explanation:

It is given that,

Initial speed of the car, u = 0 (at rest)

Acceleration of the car, $a=5\ m/s^2$

Distance covered, d = 200 m

We know to find the time taken by the car. It can be calculated using second equation of kinematics as :

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$t=\sqrt{\dfrac{2d}{a}}$

$t=\sqrt{\dfrac{2\times 200}{5}}$

t = 8.94 seconds

So, the time taken by the car is 8.94 seconds. Hence, this is the required solution.

Learn more,

Second equation of kinematics

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