How long would it take for a sample of 222^Rn that weighs 0.750 g to decay to 0.100 g? Assume a half-life for 222^Rn of 3.823 days.
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The initial Concentration is (N0) =0.705g
Final Concentraion is (N)= 0.100g
T(1/2)=3.823 days
k(rate constant)=0.6932/T(1/2)
=0.1813 /days
t=(2.303/k)xlog(N0/N)
=(2.303/0.1813)xlog(0.750/0.100)
= 12.702x0.87
=11.051 days----->Answer
Final Concentraion is (N)= 0.100g
T(1/2)=3.823 days
k(rate constant)=0.6932/T(1/2)
=0.1813 /days
t=(2.303/k)xlog(N0/N)
=(2.303/0.1813)xlog(0.750/0.100)
= 12.702x0.87
=11.051 days----->Answer
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