how long would it take for sample of 222Rn that weighs 0.750 g to decay to 0.100 g ? assume a half - life for 222Rn of 3.823 days
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assuming first order reaction
k(rate constant) for 1st order reaction is = 0.693/t(1/2) = 0.693/3.823 = 0.181days⁻¹
now
t = 2.303*log(N⁰/Nt) / k(rate constant)
where N°= no. of moles initially = 0.75/222 = 0.0033
Nt = no. of moles left after time t = 0.100/222 = 0.00045
on solving gives ,
t = 11days
i hope my answer is right ..ya but method is absolutely true
k(rate constant) for 1st order reaction is = 0.693/t(1/2) = 0.693/3.823 = 0.181days⁻¹
now
t = 2.303*log(N⁰/Nt) / k(rate constant)
where N°= no. of moles initially = 0.75/222 = 0.0033
Nt = no. of moles left after time t = 0.100/222 = 0.00045
on solving gives ,
t = 11days
i hope my answer is right ..ya but method is absolutely true
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