Question

how mamy grams of CH3COOH should be mixed in 200 ml of h20 to prepare 0.5 M CH3COOH solution​

Answer 1

M of acetic acid= 60

we know, 1000 ml 1 molar acetic acid solution = 60 g of acetic acid.

so, amount of acetic acid required to prepare 200 ml 0.5 M solution= 6 g