Question

How many 1/3 inch cubes does it take to fill a box with width 2 2/3 inches, length 3 1/3 inches, and height 2 1/3 inches?

Answer 1

Given:

A box with width 2 2/3 inches, length 3 1/3 inches, and height 2 1/3 inches

To find:

No. of 1/3 inch cubes to fill the box

Solution:

We will convert the dimensions of the given box into simple fractions for easy calculations.

The dimensions of the given box:

Length = $3\frac{1}{3} \:inches = \frac{10}{3}\:inches$

Breadth = $2\frac{2}{3} \:inches = \frac{8}{3}\:inches$

Height = $2\frac{1}{3} \:inches = \frac{7}{3}\:inches$

The side of each cube = $\frac{1}{3} \:inches$

Therefore,

The no. of cubes required to fill the box is,

= $\frac{Volume \:of\: the\: box}{Volume\:of\:each\:\frac{1}{3} \:inch \:cube}$

= $\frac{\frac{10}{3} \times \frac{8}{3} \times \frac{7}{3} }{(\frac{1}{3})^3}$

= $\frac{(\frac{1}{3} )^3\times10 \times 8 \times 7 }{(\frac{1}{3})^3}$

= $10 \times 8 \times 7$

= $\bold{560}$

Thus, it takes 560 1/3 inch cubes to fill a box with width 2 2/3 inches, length 3 1/3 inches, and height 2 1/3 inches.

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Answer 2

Answer:

Step-by-step explanation:

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