Question

How many 1's are there in the binary form of 8*1024 + 3*64 + 3

Answer 1

on solving we will get 8387 which is equal to 10000011000011
your answer is 5

Answer 2

Answer:

5

Step-by-step explanation:

How many 1's are there in the binary form of 8*1024 + 3*64 + 3

3 = 2^0 + 2^1 = 1 + 10 = 11

64 = 2^6 = 1000000

3 * 64 = 1000000 + 1000000  + 1000000  

1000000 + 10000000 = 11000000

1024 = 2^10 = 10000000000

8 * 1024 = 10000000000 + 10000000000 + 10000000000 + 10000000000 +10000000000 + 10000000000 + 10000000000 + 10000000000

= 10000000000 + 10000000000 + 10000000000 + 10000000000 +10000000000 + 10000000000 + 100000000000

= 10000000000 + 10000000000 + 10000000000 + 10000000000 +10000000000 +  110000000000

= 10000000000 + 10000000000 + 10000000000 + 10000000000 + 1000000000000

= 10000000000 + 10000000000 + 10000000000 + 1010000000000

= 10000000000 + 10000000000 + 1100000000000

= 10000000000 + 1110000000000

= 10000000000000

Adding all

11 + 11000000 + 10000000000000

= 10000011000011

There are total 5 1's