How many 117ohm resistor are required to Carry 5A on 220v line.
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Explanation:
Given: Individual resistance, R=176 Ω
I=5 A
V=220 V
Let number of resistors be n.
Then, R
1
=R
2
=......=R
n
=R=176 Ω............(i)
For resistors in parallel,
R
eq
1
=
R
1
1
+
R
2
1
+.....
R
n
1
..........(ii)
From (i) and (ii),
R
eq
=176/n...........(iii)
By ohm's Law,
V=IR
eq
220=5R
eq
...............(iv)
Substituting (iii) in (iv),
220=5×176/n
n=4
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