how many 120 ohm resistors (in parallel) are required to carry 11 ammeter on 220 volts
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Answer:
Total 6 resistors are required.
Explanation:
V/R=I ( ohm's law)
220/R=11
R=20 ohm
So effective resistance must be 20 ohm
1/R effective =n/R
From this we get
1/20 =n/120
#n=6
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