Question

How many 132 ohm resistors in parallel are required to carry 5A on a 220 V line ? ​

Answer 1

Answer:

5808 resistors

Explanation:

R= V/ I , R= 220/5 ;R= 44 . Since it is connected in Parallel let x be no: of Resistors Therefore x/132 = 44 ;x= 5808.

Answer 2

Given:

The supply voltage = 220V

The supply current = 5A

The magnitude of individual resistor = 132 Ω

To Find:

The number of resistors required in parallel

Solution:

Three 132 ohm resistors in parallel are required to carry 5A on a 220 V line.

When resistors are connected in parallel, they have the same voltage across their terminals.

For n resistors of resistances R each, the equivalent resistance Req is given by the formula:

$\frac{1}{R_e_q} = \frac{n}{R}$       - (1)

For the given circuit, the supply voltage and the current is 220V and 5A respectively.

Using Ohm's Law, V = IReq

or Req = 220 / 5

= 44 Ω

Substituting the value of Req in equation 1,

1 / 44 = n / 132

or 132 = 44 n

or n = 3