Physics, asked by rishitha2327, 5 hours ago

How many 132 ohm resistors (in parallel) are required to carry 5A current on a 110 V line?

Answers

Answered by sandhyapuvvada

1

Answer:

6 resisters

Explanation:

V=IR

R=V/I

IN PARALLEL COMBINATION,

Let the no of resistors =x

132/X=110/5

132/X=22

132=22X

X=132/22

X=6

SO,ANSWER IS 6 RESISTORS

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