How many 132Ω resistors (in parallel) are required to carry 5A in 220V line?
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Answer:
5808 RESISTORS
Explanation:
connected in Parallel let x be no: of Resistors Therefore x/132 = 44 ;x= 5808.
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Answer:
How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Ans: For x number of resistors of resistance 176 Ω, Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as From Ohm’s law, ∴four resistors of 176 Ω are required to draw the given amount of current.
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