How many 132 Ω resistors should be connected in parallel to carry 5 A current in 220 V line?
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Answered by
1
Answer:
the register that could be connected in parallel combination of 132 ohm resistor to carry 5 ampere current in 220 volt line are 27 thank you I hope you like the answer
Answered by
2
Answer:
Explanation:
i = 5A
v = 220v
using formula
r = v/i
r = 220/5
r = 44ohm.
132/n = 44
n = 132/44
n = 3
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