Question

How many 16k * 4Ram are required to have a memory with capacity 128 kilobytes ?​

Answer 1

Explanation:

Number of chips required= Required size/given size.

Required size = 16 Kb

1kb = 1024 bytes

1 byte = 8 bits

therefore 16 KB = 16 * 1024 * 8 bits.

Now, we have 12 address lines and 4 data lines,

12 address lines means 2^12 bytes which is equal to 4096 bytes.

Generally,

1024 * 8 means that 1024 locations are there and each location can store 8 bits.

1024 * 2 means that 1024 locations are there and each location can store 2 bits.

Data lines means no of bits.

Therefore as per the question given above only 4 data lines are there which means only 4 bits can be stored.

So, 4094 * 4 indicates 4096 location are there and each location can store 4 bits.

therefore the answer to the question is

16*1024*8bits/4096*4bits