how many 176 ohm resistors are required to carry 5A on a 220V line?
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Let the no. of resistor be x .
By using Ohm's Law ,
V = IR
V= 176× 5
V= 880 v
so , when connected in parallel ,
x/880 = 1 / 220
x = 880/220
x = 4
By using Ohm's Law ,
V = IR
V= 176× 5
V= 880 v
so , when connected in parallel ,
x/880 = 1 / 220
x = 880/220
x = 4
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