Question

how many 176 ohm resistors in a parallel are required to carry 5 a on a 220 v line?​

Answer 1

Answer:

Four resistances

Explanation:

Let n number of resistances are applied in a parallel combination.

Then their equivalent resistance = 176/n ohms

According to ohm's law :

Req = V/I

176/n = 220/5

176/n = 44

So, n = 176/44

n = 4 resistances