Physics, asked by prnsasi01, 11 months ago

How many 176 ohm resistors in parallel are required to carry 5 A current on a 220 V line?

Answers

Answered by ItzMissGoogle
9

Given,

P. d = 220 V

I = 5A

Finding resistance, we get :-

R = V/I

R = 44 ohm

Let the no.of resistors be x

R = 176/x

44 = 176/x

x = 4.

Hence, no. Of resistors = 4.

Hope it helps :)

Answered by Anonymous
20

\huge\mathfrak\red{Question :- }

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

\huge\mathfrak\red{Answer :- }

➤ voltage= 220V

➤ Current = 5A

➤ Resistance = V/I = 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44= 4

Number of resistors used = 4

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