Physics, asked by baliyannikita007, 8 months ago

how many 176 ohm resistors ( in parallel )are required to carry 5A on a 220 v line ?​

Answers

Answered by IntrinsicallyCurious
2

Answer:

4 resistors in parallel connection.

Explanation:

v=ir

r=v/i

r=220/5 = 44

1/44=n(1/176)

n=176/44

n=4

and that's the answer.

Answered by Anonymous
20

\huge\mathfrak\red{Question :- }

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

\huge\mathfrak\red{Answer :- }

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44= 4

Number of resistors used = 4

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