how many 176 ohm resistors ( in parallel )are required to carry 5A on a 220 v line ?
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Answered by
2
Answer:
4 resistors in parallel connection.
Explanation:
v=ir
r=v/i
r=220/5 = 44
1/44=n(1/176)
n=176/44
n=4
and that's the answer.
Answered by
20
How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?
➤ voltage= 220V
➤ Current = 5A
➤ Resistance= 44ohm
➤ Resistance of 44ohm is required
if we have same resistors is
⇒ R = R'/n
where n is number of resistor used
Here R'= 176ohm and R is 44 ohm
⇒ n= R'/R = 176/44= 4
Number of resistors used = 4
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