how many 176 ohm resistors in parallel are required to carry 5A current on a 220V line
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2
Answer:
R = v/a
R = 220/5 = 44 ohm
let number of resistances be n
so in parallel
n/176 = 1/44
n =4
Answered by
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How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?
➤ voltage= 220V
➤ Current = 5A
➤ Resistance= 44ohm
➤ Resistance of 44ohm is required
if we have same resistors is
⇒ R = R'/n
where n is number of resistor used
Here R'= 176ohm and R is 44 ohm
⇒ n= R'/R = 176/44= 4
Number of resistors used = 4
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