Question

How many 176 ohm resistors in parallel are required to carry 5 amperage on a 220 volt line?

Answer 1

V=220v
I=5 A
R=220/5=44 ohm
Let no. of resistor =n

ATQ
1/176 × n = 1/44
n= 176/44
n=4 Resistors {Answer}

Hope it helps you and please Mark as brainliest answer.

Answer 2

==============ⓢⓦⓘⓖⓨ

$\bold\red{hello...frd\:swigy\:here}$

$\bold\green{Your\:Answer:-}$

Let the total no. of resistors = x

Given,

I = 5 A

V = 220 V

According to Ohm’s law,

V = IR

R = V/ I = 220/5 = 44Ω

Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω.

1/44 = 1/176 + 1/176 + 1/176 .....χ times

1/44 = x / 176

=> x = 176/ 44

=> x = 4

Therefore, 4 resistors of 176 Ω are required to draw the given amount of current.

I hope, this will help you___❤❤

Thank you

✿┅═══❁✿ $\bold\green{BeHappy}$ ✿❁═══┅✿