Question

HOW MANY 176 OHM RESISTORS IN PARALLEL COMBINATION ARE REQURIED TO CARRY 5 A ON A 220V LINE

Answer 1

For x number of resistors of resistance 176 Ω,

Here Supply voltage, V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

$\frac{1}{r} = x \times \frac{1}{176} \\ r = \frac{176}{x}$
From Ohm's law,
$\frac{v}{i} = \frac{176}{x} \\ x = 176 \times \frac{i}{v} = \frac{176}{5} \times 220 \\ = 4$
Therefore, four resistors of 176 ohm are required to draw the required amount of current.

Thanks

Answer 2

Here Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as. From Ohm s law, four resistors of 176 ? are required to draw the given amount of current.