Question

How many 176 ohm resistors (in parallell) are
required to carry 5 A on a 220 V line?​

Answer 1

Answer:

4 Resistors are required

Step-by-step explanation:

Given:

Volts = 220 Volts

Current = 5 Ampere

Resistance of each resistor, R = 176 Ohms

No of resistors = n

We know that:

v = RpI

∴ v = \frac{R}{n}Iv= n/r

I (( ∵ \frac{1}{Rp} = n(\frac{1}{R})

Rp

1

=n(r-1)

Taking N to the other side we get,

n = \frac{RI}{V}n= V/RI

n = \frac{176 * 5}{220}n=

220

176∗5

n = 4n=4

Here u go ur answer....

Answer 2

$\huge\mathfrak\red{Question :- }$

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

$\huge\mathfrak\red{Answer :- }$

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44= 4

Number of resistors used = 4