how many 176 ohm resistors in parlell are required to carry 5A current in a 220 V line
Answers
Answered by
0
Answer:
4
Explanation:
first you have to calculate the value of one resistor thaen you have to divide it by total resistance to get answer
Answered by
1
Answer:
R=V/I
R=220÷5= 44
let X be the required number of 176 ohm resistors
Total resistance = 44 ohm
Resistors in parallel :
1/Rp = 1/R1 + 1/R2 ..
1/44 = X (1/176)
X= 176÷44 = 4
X= 4
Four 176 ohm resistors in parallel are required to carry 5A current in a 220V line
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