Question

how many 176 ohm's resistor in parallel are required to carry 5 A metre on a 220 V line

Answer 1

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Let the total no. of resistors = x

Given,

I = 5 A

V = 220 V

According to Ohm’s law,

V = IR

R = V/ I = 220/5 = 44Ω

Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω.

1/44 = 1/176 + 1/176 + 1/176 .....χ times

1/44 = x / 176

=> x = 176/ 44

=> x = 4

Therefore, 4 resistors of 176 Ω are required to draw the given amount of current.

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Answer 2

$\huge\mathfrak\red{Question :- }$

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

$\huge\mathfrak\red{Answer :- }$

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44= 4

Number of resistors used = 4