Question

how many 176 resistance (in parallel) are required to carry 5A on a 220 V line​

Answer 1

Answer:

220/5=176/n

n = 176/44

n = 4 resistors

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Answer 2

Answer:

For x number of resistors of resistance 176 Ω,

Here Supply voltage, V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

1/r=x* 1/176

r=176/x

From Ohm’s law,

v/1=176/x

x=176*1/v

=176*5/220=4

Explanation:

∴four resistors of 176 Ω are required to draw the given amount of current.