Question

HOW many 176 resistors (in parallel)are required to carry 5A on a220V line

Answer 1

Answer:

4 resistors

Explanation:

V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

1/R=x *1/176

R=176/x

From Ohm’s law,

R=V/I

176/x=220/5

x=176*5/220

=4

∴four resistors of 176 Ω are required to draw the given amount of current.

Answer 2

$\huge\mathfrak\red{Question :- }$

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

$\huge\mathfrak\red{Answer :- }$

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44= 4

Number of resistors used = 4