Question

how many 176 resistors ( in parallel ) are required to carry 5A on a 220 V line?​

Answer 1

Answer:

let us assume there is n number of resistor required. since all the resistors are connected in parallel connection so the equivalence resistance = R = 176/n Ω

Using ohms law

V =IR

220 = 5×(176/n)

n = (176×5)/220

n = 880/220 = 4

So the number of resistor would be 4