Question

How many 176 resistors (in parallel) are required to carry 5A on a 220V line?
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Answer 1

Answer:

4 resistors of 176 Ω are required to carry 5A on 220V line.

Explanation:

Let resistors be ‘x’.

Equivalent resistance = R.

=> 1/R = x (1/176)

=> R = 176/x

Using ohm's law,

• V = IR

=> V = IR

=> R = V/I

=> V/I = 176/x

=> x = 176×I/V

=> 176×5/220

=> 4

$\therefore$ 4 resistors of 176 Ω are required to carry 5A on 220V line.

Answer 2

Answer:

4 resistors of 176 Ω are required to carry 5A on 220V line.

Explanation:

Let resistors be ‘x’.

Equivalent resistance = R.

=> 1/R = x (1/176)

=> R = 176/x

Using ohm's law,

V = IR

=> V = IR

=> R = V/I

=> V/I = 176/x

=> x = 176×I/V

=> 176×5/220

=> 4

$\therefore$ 4 resistors of 176 Ω are required to carry 5A on 220V line.

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