Question

How many 17622 resistors (in parallel) are required to carry 5 A
on a 220V line?
​

Answer 1

Answer:

762168 Resistors

Explanation:

Given i=v/r

so, r=v/i

r=220/5

r=44

R= 762168 ohm

x * 1/17622 = 44ohm

(where x is the number of resistors, and since it is in parallel, reciprocal of 17622 is taken)

x= 17622 * 44

x= 762168 Resistors in parallel

Answer 2

$\huge\mathfrak\red{Question :- }$

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

$\huge\mathfrak\red{Answer :- }$

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44= 4

Number of resistors used = 4