Question

how many 176ohm resistor in parallel are required to carry 5 A on a 220 vline​

Answer 1

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Answer 2

Answer:

First calculate net resistance

R = V / I = 220 / 5 = 44 ohm

Now let n resistance of 176 ohm are required to join in parallel such that there net is 44 ohms .

There net will be

$\frac{176}{n} = 44 \\ \\ n = \frac{176}{44} = 4$